Rosie Huntington-Whiteley is set to launch her first swimwear line in April.
The 29-year-old model joined forces with Marks and Spencer in 2012 to launch her lingerie line titled Rosie for Autograph, and the blonde beauty has announced she will expand her collection to include a beachwear capsule next month.
The catwalk icon - who is expecting her first child with her partner and actor Jason Statham - announced the "exciting news" on her Instagram account.
The British star shared a string of images of her in a one-shoulder bikini whilst swimming on her photo-sharing site.
She captioned the posts: "#RosieForAutograph Swim coming April 2017!
"Very excited to announce the launch of #RosieForAutograph Swim coming April 2017 @marksandspencer! (sic)."
And Rosie has had a busy few weeks as she recently launched her Spring/Summer 2017 underwear creations for the longstanding retail company, which is also known as M&S.
Alongside images of the star in floral printed two piece sets, she wrote: "Spring has sprung! New #RosieForAutograph arrivals, only @marksandspencer #LinkInBio
"New Spring' 17 #RosieForAutograph arrivals, only @marksandspencer #LinkInBio (sic)."
The 'Mad Max: Fury Road' actress teased she would be adding more products to her Marks and Spencer fashion range earlier this week.
Rosie shared an image of her sporting a cream silk cover up and a hat, which she captioned: "Fun day shooting #RosieForAutograph beauty today, looking forward to releasing lots of new and exciting products launching soon! Big thanks to the dream team @marksandspencer @studio_jackson @kateleemakeup @cwoodhair @chercoulter (sic)."
And as well as Rosie's Marks and Spencer's designs she has also unveiled her Spring/Summer 2017 collection with Paige Denim, which was photographed at Philip Dixon house in Venice Beach, California, after being announced as their brand ambassador in 2014.
Alongside a short video of Rosie wearing the new range in a variety of polaroid pictures, which was posted on her social media account, it read: "#RosieHWxPAIGE (sic)."